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Configuration = 105
cycles = (10 5 2 7 3)(9 6 1 8 4)

a = 1, b = 4, c = 6
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cycles = (10 2 4 7 5)(9 6)(8 1)(3)

a = 2, b = 4, c = 10
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cycles = (10 5 3)(9)(8)(7 4)(6 1)(2)

a = 4, b = 6, c = 7
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cycles = (10 6 3)(9)(8)(7 1 4)(5)(2)

a = 1, b = 4, c = 7
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cycles = (10 3 6)(9)(8)(7)(5)(4)(2)(1)